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What is the slope of the line that passes through the points (-10,-8) and
(-8, -16)? Write your answer in simplest form.

Sagot :

Answer:

m=−4

Step-by-step explanation:

Step 1: Plug in the values into the slope formula.

[tex]m=\frac{y^2-y^1}{x^2-x^1}[/tex]

[tex](x^1, y^1)= (-10,-8)[/tex]

[tex](x^2, y^2)= (-8,-16)[/tex]

[tex]m= \frac{-16-(-8)}{-8-(-10)}[/tex]

Step 2: Solve.

[tex]m=\frac{-8}{2}[/tex]

Step 3: Write in simplest form.

[tex]m= -4[/tex]

Exaplanation: Because we are already given two points from the line, we can find the slope of the line. I plugged in the values into the slope formula, then subtracted. To bring the answer to simplest form, I divided. If you have any questions or find that my work is wrong, please let me know. Thanks.

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