Answered

Get insightful responses to your questions quickly and easily on IDNLearn.com. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.

Both sets of values have an average of 13. Is Set A's standard deviation smaller, larger, or about the same as Set B's? (Note: This question can be answered by knowing the concept of standard deviation, without actually computing the standard deviation). Set A: 1 2 3 23 24 25 Set B: 9 10 11 14 16 18

Sagot :

Leenaidn

Hi there!

Set A has a LARGER standard deviation.

A set's standard deviation is equivalent to:

[tex]\sigma = \frac{\sqrt{\Sigma (x - \mu)^2 }}{n-1}[/tex]

σ = standard deviation

x = value

μ = mean

n = # of observations

Basically, standard deviation is calculated using how far apart EACH value is from the set's mean. If more values are FARTHER away from the mean, the standard deviation increases and vice-versa.

Set A has a GREATER RANGE and its values are farther from 13 on both sides compared to Set B which has a SMALLER RANGE and its values are closer to 13.

Therefore, Set A will have a larger standard deviation.

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.