Answered

IDNLearn.com is your go-to resource for finding precise and accurate answers. Find reliable solutions to your questions quickly and easily with help from our experienced experts.

A circular disk is rotating about a central axis with an angular velocity which is increasing at a constant rate. Point 1 on the disk is located at a distance r1 from the center of the disk and point 2 on the disk is located at a distance r2 from the center of the disk. If r2 = 2r1, which of the following ratios is the largest? 1 and 2 refer to being at points 1 and 2 in the subscripts below, all values occurring at the same time.

a. ω2/ω1
b. α2/α1
c. ac2/ac1
d. All the ratios are 1 so none is larger.

Sagot :

Onyebuchinnajiidn

The largest ratio of the circular disk at the two points is ac2/ac1.

The given parameters:

  • Location of point 1 = r1
  • Location of point 2 = r2 = 2r1

What is angular speed?

  • The angular speed of an object is the rate of change of angular displacement of the object.

The angular speed of each disk is given as;

[tex]\omega = 2\pi N[/tex]

where;

  • N is the number of revolutions

thus, the angular speed is independent of radius of the circular disk

ω2/ω1 = 1

the centripetal acceleration of each disk is calculated as follows;

[tex]a_c = \frac{v^2}{r} \\\\a_c_1 = \frac{v^2}{r_1} \\\\a_c_2 = \frac{v^2}{2r_1} \\\\\frac{a_c_2}{a_c_1} = \frac{2r_1}{v^2} \times \frac{v^2}{r_1} = 2[/tex]

the angular  acceleration of the disk is calculated as follows;

[tex]\alpha = \frac{\omega }{t}[/tex]

the angular acceleration is independent of the radius of the disk.

α2/α1 = 1

Thus, the largest ratio of the circular disk at the two points is ac2/ac1.

Learn more about centripetal acceleration here: https://brainly.com/question/79801

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.