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7) Find five consecutive integers such that the sum of the first three
numbers equals 2 times the fifth number.


Sagot :

Answer:  5, 6, 7, 8, 9

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Explanation:

Consecutive integers are ones that follow one right after another. Some examples include:

  • 1,2,3,4,...
  • 7,8,9,...
  • 210,211,212,213,...

We don't know what the starting value is, so let's say its x. The next number after that is x+1. Then after that is (x+1)+1 = x+2. And so on.

  • first = x
  • second = x+1
  • third = x+2
  • fourth = x+3
  • fifth = x+4

The sum of the first three terms is equal to twice the fifth number, so,

(first) + (second) + (third) = 2(fifth)

(x) + (x+1) + (x+2) = 2(x+4)

3x+3 = 2x+8

3x-2x = 8-3

x = 5

The starting item is 5. The next is 6 and so on.

  • first = x = 5
  • second = x+1 = 5+1 = 6
  • third = x+2 = 5+2 = 7
  • fourth = x+3 = 5+3 = 8
  • fifth = x+4 = 5+4 = 9

The five numbers are: 5,6,7,8,9

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Check:

Summing the first three terms = 5+6+7 = 11+7 = 18

Twice the fifth term = 2*9 = 18

The answer is confirmed.