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A rescue plane travels horizontally at 30.0m/s 200.0m above the ground. it drops a supply package.

Sagot :

Answer:

i think u times them im not sure but then divide

Explanation:

Saifan21khanidn

Answer:

The horizontal distance of the package fall before landing is (30 m/s)*(time to fall 200 m). Furthermore the velocity of the package just before it hits the ground is - g*t is the vertical component

30 m/s is the horizontal component.

t is the time required to fll H = 200 m, which is

sqrt(2H/g)

You do the numbers

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