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The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.
Given the following data:
To determine the specific heat capacity of this chunk of metal:
Mathematically, quantity of heat is given by the formula;
[tex]Q = mc\theta[/tex]
Where:
Making c the subject of formula, we have:
[tex]c = \frac{Q}{m\theta}[/tex]
Substituting the given parameters into the formula, we have;
[tex]c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }[/tex]
Specific heat, c = 0.32 J/g°C.
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