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Find three consecutive odd integers for which the sum of the first and the second is equal to nine more than the third.

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Answer:

  11, 13, 15

Step-by-step explanation:

Let x represent the middle of the three integers.

  (x -2) +x = (x +2) +9 . . . . the given relation

  2x -2 = x +11 . . . . simplify

  x = 13 . . . . . add 2-x

The integers are 11, 13, 15.

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