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Sagot :
The final speed of the skydiver at the point is 44.3 m/s
Determination of the time
We'll begin by calculating the time required to fall 100 m
- Height (h) = 100 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) =?
H = ½gt²
100 = ½ × 9.8 × t²
100 = 4.9 × t²
Divide both side by 4.9
t² = 100 / 4.9
Take the square root of both side
t = √(100 / 4.9)
t = 4.52 s
Determination of the velocity
Finally, we shall determine the velocity.
- Time (t) = 4.52 s
- Acceleration due to gravity (g) = 9.8 m/s²
- Velocity (v) =?
v = gt
v = 9.8 × 4.52
v = 44.3 m/s
Learn more about motion under gravity:
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Answer:
I did this in school v^2 = u^2 + 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Since he dropped from a height, u = 0 m/s
v^2 = 0^2 + 2 (10) (100)
v^2 = 2000
v = √2000
v = 44.7 m/s
Explanation:
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