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Using Venn probabilities, it is found that 240 students are enrolled in both classes.
The events are:
The supposed percentages, which also represents the probabilities involving a single student, are:
The percentage involved in both is:
[tex]P(A \cap B) = P(A) + P(B) - P(A \cup B)[/tex]
Hence:
[tex]P(A \cap B) = 0.5 + 0.4 - 0.7 = 0.2[/tex]
Then, out of 1200 students:
[tex]0.2(1200) = 240[/tex]
240 students are enrolled in both classes.
To learn more about Venn probabilities, you can take a look at https://brainly.com/question/25698611