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A box of chocolates contains four milk chocolates, five dark
chocolates, and three white chocolates. You randomly
select one chocolate. What is the probability that t is a milk
chocolate or a dark chocolate?
Express your answer as a fraction in simplest form.

Sagot :

Answer:

10 Milk chocolates

8 dark chocolates

6 white chocolates

24 TOTAL

\frac{10}{24} Probability that Hanissa choose a milk chocolate

Now, since she has already eaten one chocolate, then what's left is 23 chocolates.

So, since the second one should be a white chocolate and there are 6 of them, then

\frac{6}{23} - probability of choosing a white chocolate.

Then, multiply,

( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}

Answer: 5/46 or 10.87%

Step-by-step explanation: no explanation:

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