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Answer:
[tex]\frac{x^4-x^3-19x^2-10x+17}{x-5}=x^3+4x^2+x-5+\frac{-8}{x-5}[/tex]
Step-by-step explanation:
5 | 1 -1 -19 -10 17
___ 5 20_ 5 -25____
1 4 1 -5 | -8
So, we show our answer as [tex]1x^3+4x^2+1x-5+\frac{-8}{x-5}=x^3+4x^2+x-5+\frac{-8}{x-5}[/tex]