Answered

Explore IDNLearn.com's extensive Q&A database and find the answers you need. Explore a wide array of topics and find reliable answers from our experienced community members.

An Olympic high jumper leaps over a horizontal bar. The jumper's center of mass is raised 0.25 m during the jump. Calculate the minimum speed with which the athlete must leave must leave the ground to perform this feat.

Sagot :

Eduard22slyidn

The minimum speed with which the athlete must leave the ground is 2.21 m/s

From the question given above, the following data were obtained:

  • Maximum Height (h) = 0.25 m
  • Final velocity (v) = 0 (at maximum height)
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Initial velocity (u) =?

v² = u² – 2gh (going against gravity)

0² = u² – (2 × 9.8 × 0.25)

0 = u² – 4.9

Collect like terms

u² = 0 + 4.9

u² = 4.9

Take the square root of both side

u = √4.9

u = 2.21 m/s

Thus, the athlete must leave the ground with a minimum speed of 2.21 m/s.

Learn more about projectile motion:

https://brainly.com/question/15604286

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.