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smaller leg be x
Using Pythagorean theorem
[tex]\\ \sf\longmapsto x^2+(x+5)^2=(x+10)^2[/tex]
[tex]\\ \sf\longmapsto x^2+x^2+10x+25=x^2+20x+100[/tex]
[tex]\\ \sf\longmapsto x^2-10x-75=0[/tex]