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A 3.28 L solution is prepared by dissolving 535 g CaCl2 in water. The molar mass of CaCl2 is 110.98 g. What is the morality of the solution?

Sagot :

Transitionstateidn

Answer:

              1.47 mol/L

Explanation:

Molarity is given as,

                           Molarity = Moles / Vol in L    ------- (1)

Moles of CaCl₂,

                           Moles = Mass / M.Mass

                           Moles = 535 g / 110.98 g/mol

                           Moles = 4.82 mol

Now, putting values in eq. 1.

                           Molarity = 4.82 mol / 3.28 L

                           Molarity = 1.47 mol/L

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