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A canoe, which has a speed of 2.40 m/s in still water, is headed North as it crosses a river flowing East at 1.60m/s. What is the magnitude of the canoes' resultant velocity with respect to the shore.

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The resultant velocity of the canoe is 2.88 m/s.

The Resultant velocity of the river can be calculated using Pythagoras Theorem

Pythagoras Theorem:

In a right angle triangle, The square of the hypotenuse is equal to the sum of the square of the two other sides.

Note: In a cardinal point, The north and the east are at right angle.

Formula:

  • a² = b²+c²............... Euqation 1

Where:

  • a = resultant velocity of the canoe
  • b = speed of the canoe
  • c = velocity of the flowing river.

From the question,

Given:

  • b = 2.4 m/s
  • c = 1.6 m/s

Substitute these values into equation 1

  • a² = 2.4²+1.6²
  • a² = 5.76+2.56
  • a² = 8.32
  • a = √8.32
  • a = 2.88 m/s

Hence, the resultant velocity of the canoe is 2.88 m/s

Learn more about resultant velocity here: https://brainly.com/question/24767211

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