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y= 2x-1 is a tangent to y=x^2. Name the point of tangency,

Sagot :

Answer:

Point of tangency is [tex]x=1[/tex] or [tex](1,1)[/tex]

Step-by-step explanation:

You don't really need to use Calculus here. You can just set each equation to each other and solve for x (the point of tangency):

[tex]x^2=2x-1[/tex]

[tex]x^2-2x+1=0[/tex]

[tex](x-1)(x-1)=0[/tex]

[tex]x=1[/tex]

Therefore, the point of tangency is [tex]x=1[/tex] or [tex](1,1)[/tex]

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