Answered

Explore a diverse range of topics and get expert answers on IDNLearn.com. Discover in-depth and trustworthy answers to all your questions from our experienced community members.

How many moles are present in 25.0 grams of potassium
permanganate, KMnO4?

Sagot :

Samueladesida43idn

0.158 moles of KMnO4 are present in 25.0 grams of potassium permanganate, KMnO4.

NUMBER OF MOLES:

  • The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass. That is;

no. of moles = mass (g) ÷ molar mass (g/mol)

  • According to this question, there are 25 grams of potassium permanganate (KMnO4).

The molar mass of KMnO4 = 39 + 55 + 16(4) = 158g/mol

no. of moles = 25g ÷ 158g/mol

no. of moles = 0.158mol

Therefore, 0.158 moles of KMnO4 are present in 25.0 grams of potassium permanganate, KMnO4.

Learn more about number of moles at: https://brainly.com/question/14919968

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.