Find the best solutions to your problems with the help of IDNLearn.com. Our platform is designed to provide quick and accurate answers to any questions you may have.
0.158 moles of KMnO4 are present in 25.0 grams of potassium permanganate, KMnO4.
no. of moles = mass (g) ÷ molar mass (g/mol)
The molar mass of KMnO4 = 39 + 55 + 16(4) = 158g/mol
no. of moles = 25g ÷ 158g/mol
no. of moles = 0.158mol
Therefore, 0.158 moles of KMnO4 are present in 25.0 grams of potassium permanganate, KMnO4.
Learn more about number of moles at: https://brainly.com/question/14919968