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[tex]\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=x+7\\ b=2x+12 \end{cases}\implies A=\cfrac{1}{2}(2x+12)(x+7) \\\\\\ A=\cfrac{1}{2}\underset{\stackrel{\uparrow \qquad }{\textit{common factoring}}}{2(x+6)(x+7)}\implies A=(x+6)(x+7)\implies A=\stackrel{\mathbb{F~O~I~L}}{x^2+13x+42}[/tex]