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[tex] {d}^{2} \div (4c) - b + 5a \\ = {(8)}^{2} \div( 4 \times 2) - 3 + 5 \times \frac{1}{5} \\ = 64 \div 8 - 3 + 1 \\ = 8 - 3 + 1 \\ = 9- 3 \\ = 6[/tex]
Answer:
6
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