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Given that f(x)= x^2-3/2 find f^-1(x)

Sagot :

ThePerfectionOne01idn

Answer:

[tex]\bold{f(x)=-\frac{1}{2}}[/tex]

Step-by-step explanation:

[tex]f(x)= x^2-\frac{3}{2}[/tex]              replace x with -1

[tex]f(x)= -1^2-\frac{3}{2}[/tex]           solve exponents

-1² = -1 × -1 = 1

[tex]f(x)= 1-\frac{3}{2}[/tex]                subtract

[tex]\bold{f(x)=-\frac{1}{2}}[/tex]

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