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A box of mass 15 kg placed on horizontal 4 floor is pulled by a horizontal force. What will be the work done by the force if the coefficient of sliding friction between the box and the surface of the floor is 0.3 and body moved at unit distance.​

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LammettHashidn

The net force on the box perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the box. Then

F[normal] = mg = 147 N

so that

F[friction] = 0.3 F[normal] = 44.1 N

The net force parallel to the floor is

∑ F[para] = F[applied] - F[friction] = ma

where a is the acceleration of the box. Then

F[applied] = (15 kg) a + 44.1 N

Then the work done by the applied force is

W[applied] = ((15 kg) a + 44.1 N) (1 m) = (15a + 44.1) J

We can't find the exact amount of work without any more information. If the box is pulled with constant speed, then a = 0 so the work would be 44.1 J.

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