The diameter of the circular garden is equal to the side length of the
square lot.
Response:
The given parameters are;
The size of the square lot enclosing the garden = 6 m by 6 m
Location of the garden = The first quadrant
The garden is tangential to the axes of the plane, therefore, the tangents are the axes of the plane.
Required:
To find the equation of the circular garden.
Solution:
The diameter of a circle inscribed in a square is equal to the side length of the square, therefore;
Diameter of the circular garden = 6 meters
[tex]Radius = \mathbf{ \dfrac{Diameter}{2}}[/tex]
[tex]Radius \ of \ the \ circular \ garden = \dfrac{6 \, m}{2} = 3 \, m[/tex]
Therefore, the center of the circle is a radii length from each axis, which gives;
The center of the circle = (3, 3)
The general equation of a circle is presented as follows;
(x - h)² + (y - k)² = r²
Where:
(h, k) = The coordinates of the center of the circle = (3, 3)
The equation of the circle is therefore;
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