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i am just clueless!!!!!

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Sagot :

Clarch19idn

Answer:

6 units

Step-by-step explanation:

use the distance formula to find the new length of JK, which is J'K'

d = [tex]\sqrt{(y-y)^2+(x-x)^2}[/tex]

coordinates of J: (-7,3)

coordinates of J': (-7/2, 3/2)

coordinates of K: (3/2, -3/2)

d = [tex]\sqrt{(-3/2-3/2)^2+(3/2-(-3/2)^2}[/tex]

d = [tex]\sqrt{(-6/2)^2+(-10/2)^2}[/tex]

d = [tex]\sqrt{3^2+5^2}[/tex]

d = [tex]\sqrt{36}[/tex]

d = 6

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