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Evaluate the numerical value of the vertical velocity of the car at time t=0. 25s using the expression from part d, where y0=0. 75m, α=0. 95s−1, and ω=6. 3s−1.

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The vertical velocity of the car at the given position and time is 4.905 m/s.

The given parameters:

  • Initial angular velocity, [tex]\omega_0[/tex] = 6.3 rad/s
  • Time of motion, t = 0.25 s
  • Vertical displacement, y = 0.75 m
  • Angular acceleration, [tex]\alpha = 0.95 \ rad/s^2[/tex]

What is vertical velocity?

  • This is the linear velocity of an object in a vertical direction.

The angular velocity of an object in a circular motion is given as;

[tex]\omega_f = \omega _0 + \alpha t\\\\\omega _f = 6.3 \ +\ 0.95 \times 0.25 \\\\\omega _f = 6.54 \ rad/s[/tex]

The vertical velocity of the car at the given position and time is calculated as follows;

[tex]v = \omega r\\\\v = \omega_f y\\\\v = (6.54 \ rad/s)\times (0.75\ m)\\\\v = 4.905 \ m/s[/tex]

Thus, the vertical velocity of the car at the given position and time is 4.905 m/s.

Learn more about vertical velocity here: https://brainly.com/question/7358392

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