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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.

Which equations can be used to solve for y, the length of the room? Select three options.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0


Sagot :

length = y

width = y- 5

(y-5) * (y) = 750

y^2 - 5y = 750

y^2 -5y - 750 = 0

answer:

(y + 25)(y – 30) = 0