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If the initial rate of a reaction is 16 times greater as the concentration of one of the reactants is quadrupled, then the reaction is second order.
Second order reaction
A second order reaction is one in which the rate law can be written as Rate = k[A]^2 where;
- k = rate constant
- [A] = concentration of the reactant
Hence, when [A] is quadrupled, we will notice that the rate of reaction is increased by sixteen fold because; Rate = k[4A]^2 = 16.
Learn more about second order reaction: https://brainly.com/question/1195122
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