Answered

Experience the convenience of getting your questions answered at IDNLearn.com. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

What is the average oxidation state of tungsten in sodium phosphotungstate, Na3PW12O40?
(A) +6.00
(B) +6.17
(C) +6.42
(D) +6.67

Sagot :

Eduard22slyidn

The average oxidation state of tungsten, W in Na₃PW₁₂O₄₀ is +6.67

The correct answer to the question is Option D. +6.67

Oxidation number of individual elements in Na₃PW₁₂O₄₀  

  • Sodium (Na) = +1
  • Phosphorus (P) = –3
  • Oxygen (O) = –2
  • Tungsten (W) =?

The oxidation number of tungsten, W in Na₃PW₁₂O₄₀ can be obtained as follow:

Na₃PW₁₂O₄₀ = 0 (group state)

3Na + P + 12W + 40O = 0

3(1) + (–3) + 12W + 40(–2) = 0

3 – 3 + 12W – 80 = 0

12W – 80 = 0

Collect like terms

12W = 0 + 80

12W = 80

Divide both side by 12

W = 80 / 12

W = +6.67

Thus, the oxidation number of tungsten, W in Na₃PW₁₂O₄₀ is +6.67

Learn more about oxidation number:

https://brainly.com/question/2510539

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.