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determine the domain and range of F(x)=2(x+1)^2-3

Sagot :

Mausampatel55idn
domain is 0
range is -1

Answer:  domain: all real numbers.  range: [-3, infinity)

Step-by-step explanation:

We've got [tex]f(x) = 2(x+1)^2 - 3[/tex].

You can plug in any number for [tex]x[/tex] without a problem, so the domain is all real numbers, written [tex]\mathbb R[/tex].

If you graph the function, you can see it touches -3 but cannot go lower; however, it can reach anything higher than -3. Therefore the range is [tex][-3, \infty)[/tex].

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