IDNLearn.com: Your one-stop destination for reliable answers to diverse questions. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.
Sagot :
The work done on the box by the applied force is zero.
The work done by the force of gravity is 75.95 J
The work done on the box by the normal force is 75.95 J.
The given parameters:
- Mass of the box, m = 3.1 kg
- Distance moved by the box, d = 2.5 m
- Coefficient of friction, = 0.35
- Inclination of the force, θ = 30⁰
What is work - done?
- Work is said to be done when the applied force moves an object to a certain distance
The work done on the box by the applied force is calculated as;
[tex]W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)[/tex]
where;
a is the acceleration of the box
The acceleration of the box is zero since the box moved at a constant speed.
[tex]W = (0) d \times cos(30)\\\\W = 0 \ J[/tex]
The work done by the force of gravity is calculated as follows;
[tex]W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J[/tex]
The work done on the box by the normal force is calculated as follows;
[tex]W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J[/tex]
Learn more about work done here: https://brainly.com/question/8119756
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.