Answered

IDNLearn.com makes it easy to get reliable answers from knowledgeable individuals. Ask any question and get a thorough, accurate answer from our community of experienced professionals.

An arrow is shot parallel to horizontal from a height of 1.4 meters. It has a velocity of 49 m/s.

a. How long will it take to hit the ground?
b. what horizontal distance will the arrow travel

i need the answer for both please help. i need to show
work

Sagot :

Onyebuchinnajiidn

The time taken for the arrow to hit the ground is 0.53 s.

The horizontal distance traveled by the arrow is 25.97 m.

The given parameters:

  • Initial horizontal velocity, [tex]v_x[/tex] = 49 m/s
  • Initial vertical velocity, [tex]v_y[/tex] = 0

What is time of motion?

  • This is the time taken for a projectile to land on the plane of projection.

The time of motion is calculated as follows;

[tex]h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1.4}{9.8} }\\\\t = 0.53 \ s[/tex]

The horizontal distance traveled by the arrow is calculated as follows;

[tex]X = v_x t\\\\X = (49\ m/s) \times (0.53 \ s)\\\\X = 25.97 \ m[/tex]

Learn more about time of motion here: https://brainly.com/question/2364404

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.