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Two patrol boats leave Cape May at the same time, the same speed, but on different bearings. One has bearing 41°45
and the other has bearing 59°13'. How far apart will they be when they are 20 miles from Cape May?


Sagot :

Based on the information given, the computation shows that the distance between them is 2.47 miles.

Solving the distance.

Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.

The other has bearing 59°13'. This will be:

= 59° + (13/60) = 59° + 0.22 = 59.22°.

The difference of the angles will be:

= 59.22° - 41.75°

= 17.47°

Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:

c² = a² + b² - 2ab cos 17.47°

c² = 20² + 20² - (2 × 20 × 20 × 0.19)

c² = 6.07459

c = 2.47

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