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If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?



A) 50 meters
B)20 meters
C)10 meters
D)5 meters

Sagot :

Leenaidn

Hi there!

[tex]\large\boxed{\text{B) 20 meters}}[/tex]

We know that:

[tex]E_T = U + K[/tex]

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

h = 20 meters

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