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In a box there are 50 counters :white ones,blue ones and red ones .There are eleven times as many white ones as blue ones.There are less red ones than white ones, but more read ones than blue ones .By how much is the number of red counters less than the number of white counters ?

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Melody08idn

Answer:

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Mhanifaidn

Answer:

  • 33 white, 3 blue, 14 red

Step-by-step explanation:

  • White = w, Blue = b, Red = r

Given:

  • w = 11b
  • r < w
  • b < r
  • w + b + r = 50

The last equation can be written as:

  • 11b + b + r = 50
  • 12b + r = 50

Possible values of b are 1, 2, 3, 4

  • Since b < r, we exclude b = 4

If b = 1

  • w = 11,
  • r = 50 - 12 = 38 but number of red should be less than white, excluded as r < w is not met

If b = 2

  • w = 22,
  • r = 50 - 24 = 26, still same condition as above, excluded as r < w is not met

If b = 3

  • w = 33,
  • r = 50 - 36 = 14, this is the only correct option to consider
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