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prove that 1/1+sinA -1/1+sinA =2tanAsinA​

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Step-by-step explanation:

[tex] \frac{1}{1 + \sin( \alpha ) } \frac{1}{1 - \sin( \alpha ) } \\ \frac{1 - \sin( \alpha ) + 1 + \sin( \alpha ) }{(1 + \sin( \alpha ))(1 - \sin( \alpha )) } \\ = \frac{2}{1 - {sin}^{2} \alpha } \\ \frac{2}{ {cos}^{2} \alpha } = 2 \: {sec}^{2} \alpha [/tex]

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