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Answer:
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Explanation:
Apparent power (volt-amperes) is the trigonometric sum of Real power (watts) and reactive power (volt-amperes reactive - VARs). Stated mathematically: VA squared = watts squared plus VARs squared
similarly, power factor, the ratio of real power to apparent power, is the cosine of the angle between the real power leg and apparent power hypotenuse of a right triangle (Reactive power being the other leg).
Just use these relationships and a bit of high school trigonometry and you can calculate the apparent power and power factor for the system you are describing.
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The power factor of the 65-kVA load, if the overall power factor is 0.85 lagging is 0.585 lagging.
What is Apparent energy?
Apparent energy (volt-amperes) is the trigonometric sum of Real energy (watts) and reactive energy (volt-amperes reactive - VARs). Stated mathematically: VA squared = watts squared plus VARS squared similarly, energy component, the ratio of actual energy to obvious energy, is the cosine of the perspective among the actual energy leg and obvious energy hypotenuse of a proper triangle (Reactive energy being the opposite leg).
Just use those relationships and a chunk of excessive college trigonometry and you may calculate the obvious energy and energy component for the machine you're describing.
Read moe about the load :
https://brainly.com/question/2264373
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