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Which ordered pairs make the equation true?

4x – 3y = –10

Choose all answers that are correct.
(Points : 1)
(–4, –2)
(–1, 2)
(1, 4)
(3, –1)

Sagot :

Naǫidn
[tex](-4,-2) \\ x=-4 \\ y=-2 \\ \Downarrow \\ 4 \times (-4)-3 \times (-2) \stackrel{?}{=} -10 \\ -16+6 \stackrel{?}{=} -10 \\ -10 \stackrel{?}{=} -10 \\ -10 = -10 \\ \\ (-1,2) \\ x=-1 \\ y=2 \\ \Downarrow \\ 4 \times (-1)- 3 \times 2 \stackrel{?}{=}-10 \\ -4-6 \stackrel{?}{=} -10 \\ -10 \stackrel{?}{=} -10 \\ -10 = -10 \\ \\ (1,4) \\ x=1 \\ y=4 \\ \Downarrow \\ 4 \times 1-3 \times 4 \stackrel{?}{=} -10 \\ 4-12 \stackrel{?}{=} -10 \\ -8 \stackrel{?}{=} -10 \\ -8 \not= -10[/tex]

[tex](3,-1) \\ x=3 \\ y=-1 \\ \Downarrow \\ 4 \times 3- 3 \times (-1) \stackrel{?}{=} -10 \\ 12+3 \stackrel{?}{=} -10 \\ 15 \stackrel{?}{=} -10 \\ 15 \not= -10[/tex]

The ordered pairs (-4,-2) and (-1,2) make the equation true.
Rodewayidn
(x,y)
1. 
(-4,-2)
4*(-4)-3*(-2)= -10
-16+6= -10
- 10 = - 10

2. (-1,2)
4*(-1)-3*2= -10
-4-6= -10
-10 = -10

3. (1,4)
4*1-3*4= -10
8-12= -10
-4 ≠ -10

4. (3, -1)
4*3-3*(-1)= -10
12 + 3 = -10
15 ≠ -10

The correct answers:
 (-4,-2)  and  (-1,2)
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