Answered

IDNLearn.com makes it easy to find accurate answers to your specific questions. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.

Which of these statements are true? Select all that apply. The Delta. Hrxn for the reaction C(s) O2(g) Right arrow. CO2(g) is the same as the Delta. Hf for CO2(g). The Delta. Hrxn for the reaction Na(s) Cl2(g) Right arrow. 2NaCl(s) is the same as the Delta. Hf for NaCl(s). The Delta. Hf for Br2(l) is 0 kJ/mol by definition. To determine the Delta. Hf for H2O(g), just reverse the sign of the Delta. Hrxn for the reaction 2H2O(l) Right arrow. 2H2(g) O2(g). The Delta. Hf for N2(l) is 0 kJ/mol by definition. The Delta. Hrxn for the reaction 1. 5H2(g) 0. 5N2(g) Right arrow. NH3(g) is the same as the Delta. Hf for NH3(g).

Sagot :

Mickymike92idn

Based on the enthalpy changes, the true statements are:

  • ΔHrxn for the reaction C(s) + O2(g) -----> CO2(g) is the same as the ΔHf for CO2(g)
  • ΔHf for Br2(l) is 0 kJ/mol by definition.
  • ΔHrxn for the reaction 1. 5H2(g) + 0. 5N2(g) ---> NH3(g) is the same as the ΔHf for NH3(g)

Enthalpy changes

Enthalpy changes are the heat changes that occurs during a chemical reaction.

Based on enthalpy changes the following statements from the given options are true:

  • ΔHrxn for the reaction C(s) + O2(g) -----> CO2(g) is the same as the ΔHf for CO2(g) since the reaction produces CO2
  • ΔHf for Br2(l) is 0 kJ/mol by definition.
  • ΔHrxn for the reaction 1. 5H2(g) + 0. 5N2(g) ---> NH3(g) is the same as the ΔHf for NH3(g) since the product of the first reaction is the same as reaction 2.

Therefore, based on the enthalpy changes, the true statements are:

  • ΔHrxn for the reaction C(s) + O2(g) -----> CO2(g) is the same as the ΔHf for CO2(g)
  • ΔHf for Br2(l) is 0 kJ/mol by definition.
  • ΔHrxn for the reaction 1. 5H2(g) + 0. 5N2(g) ---> NH3(g) is the same as the ΔHf for NH3(g)

Learn more about about enthalpy changes at: https://brainly.com/question/14291557

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.