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Sagot :
LETS USE COMBINATION AS ORDER IS MANDATORY HERE
[tex]\\ \rm\Rrightarrow ^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]
[tex]\\ \rm\Rrightarrow ^4C_3[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{4!}{3!(1!)}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{4(3!)}{3!}[/tex]
[tex]\\ \rm\Rrightarrow 4ways[/tex]
Answer:
12
Step-by-step explanation:
It is helpful to draw a sample-space diagram of all the possible outcomes:
[tex]\large \begin{array}{| c | c | c | c |}\cline{1-4} & orange & vanilla & root\:beer \\\cline{1-4} paper & 1 & 1 & 1 \\\cline{1-4} plastic & 1 & 1 & 1 \\\cline{1-4} metal & 1 & 1 & 1 \\\cline{1-4} cardboard & 1 & 1 & 1 \\\cline{1-4}\end{array}[/tex]
Therefore, there are 12 possible outcomes.
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