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in the figure four quarters each of radius 2 m are removed from a rectangle find the perimeter

Sagot :

Answer:

in the figure four quadrants each of radius 2 m are removed from a rectangle.

I have attached the required figure, assuming the sides of a rectangle based on given measurement of quadrants.

Let the sides of a rectangle be 2 m × 4 m.

The radius of quadrant is 2 m ( given )

From given, we have

Area of figure = Area of 4 quadrants - Area of rectangle .

= 4 × π/4 × r² - l × w

= 4 × π/4 × 2² - 2 × 4

= 3.14 × 4 - 8

= 12.4 - 8

= 4.4 m²

Therefore, the area of the figure is 4.4 m²

Perimeter of figure = Perimeter of 4 quadrants - Perimeter of rectangle

= 4 × [ 0.5πr + 2r ] - 2 ( l + w )

=  4 × [ 0.5 × 3.14 × 2 + 2 × 2 ] - 2 ( 4 + 2 )

=  4 × [ 3.14 + 4 ] - 2 (6)

= 28.56 - 12

= 16.56 m

the perimeter of the figure is 16.56 m