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how much heat is required to raise the temperature of a 5.45-g sample of iron (specific heat = 0.450 j/g°c) from 25.0°c to 79.8°c?

Sagot :

Answer:

134.397 Joules

Explanation:

Using the formula:

E = C × m × Δθ (where E is Energy, C is specific heat capacity and Δθ is change in temperature)

So E = 0.45×5.45×(79.8-25)

So E = 134.397 Joules

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