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Sagot :
The width of the rectangle using synthetic division is; 5x² + 4x - 6
Synthetic division of Polynomials
We are given;
Area of rectangle = 5x³ + 19x² + 6x - 18
Length of rectangle = x + 3
We know that;
Width of rectangle = Area/length.
Using synthetic division, we have;
5x² + 4x - 6
(x + 3) | 5x³ + 19x² + 6x - 18
- 5x³ + 15x²
4x² + 6x
- 4x² + 12x
-6x - 18
-6x - 18
0
Thus, the width of the rectangle is 5x² + 4x - 6
Read more about polynomial synthetic division at; https://brainly.com/question/24323423
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