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A bicycle is traveling with a speed of 12 m/s. The cyclist hits the brakes reducing the speed to 4 m/s in a time of 4.8 seconds. What is the acceleration of bike?

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So, the acceleration of the bicycle is approximately -1.67 m/s² or it can be said to be decelerating approximately 1.67 m/s².

Introduction

Hi ! Here I will help material about linear motion changes regularly, which is where you will hear a lot of the term acceleration. Acceleration occurs when an object's speed increases in a certain time interval. Acceleration can be negative which is called deceleration. The relationship between acceleration with velocity and time is manifested in the equation:

[tex] \boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}} [/tex]

With the following conditions :

  • a = acceleration (m/s²)
  • [tex] \sf{v_2} [/tex] = object's final velocity (m/s)
  • [tex] \sf{v_1} [/tex] = object's initial velocity (m/s)
  • t = interval of the time (s)

Problem Solving

We know that :

  • [tex] \sf{v_2} [/tex] = object's final velocity = 4 m/s
  • [tex] \sf{v_1} [/tex] = object's initial velocity = 12 m/s
  • t = interval of the time = 4.8 s

What was asked :

  • a = acceleration = ... m/s²

Step by step :

[tex] \sf{a = \frac{v_2 - v_1}{t}} [/tex]

[tex] \sf{a = \frac{4 - 12}{4.8}} [/tex]

[tex] \sf{a = \frac{-8}{4.8}} [/tex]

[tex] \boxed{\sf{a \approx -1.67 \: m/s^2}} [/tex]

So, the acceleration of the bicycle is about -1.67 m/s² or it can be said to be decelerating around 1.67 m/s².

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