Connect with experts and get insightful answers to your questions on IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.
Sagot :
We have that the Velocities is mathematically given as
a)v=2.8e5m/s
b)v_2=3.11e5m/s
From the question we are told
- Consider the parallel-plate capacitor shown in the figure.
- The plate separation is 1.8 mm and the the electric field inside is 23 N/C.
- An electron is positioned halfway between the plates and is given some initial velocity, vi.
Velocity
Generally the equation for the workdone is mathematically given as
a)
[tex]-qEr=0.5m(u/2)^2\\\\Therefore\\\\1.6e-19*19*2.9e-3=0.5*9.1e-31*v^2/4[/tex]
v=2.8e5m/s
b)
applying work
[tex]-qEr=0.5m(u/2)^2\\\\1.6e-19*19*2.9e-3=0.5*9.1e-31(v_2^2-7.75e10)[/tex]
v_2=3.11e5m/s
For more information on Velocity visit
https://brainly.com/question/7359669
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.