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The value of kb of cyclohexane in the given question is; kb = 2.82 °C/m
Molality of solution = (Number of moles of C₆H₄Cl₂)/(Mass of Cyclohexane)
Now;
Number of moles of C₆H₄Cl₂ = Mass/molar mass = 2g/147 g/mol
Number of moles of C₆H₄Cl₂ = 0.0136 mol
Molality of solution = 0.0136/(22.5 * 10⁻³ kg)
Molality of solution = 0.6 m
Now, to find kb for cyclohexane, we will use the formula;
T_b(solution) - T_b(solvent) = kb × molality of solution
Thus;
82.39 - 70 = kb * 0.6
kb = (82.39 - 70)/0.6
kb = 2.82 °C/m
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