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what is the equation of the line in slope-intercept form? that has a slope of -2/5 and passes through (15,-2)
We have to write the equation of line which is passing through the point (−2,5) and parallel to the line y=3x+1. Hence, equation of straight line in point slope form is (y−5)=3(x+2) and in slope-intercept form is y=3x+11
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