Adri729idn
Answered

Join IDNLearn.com today and start getting the answers you've been searching for. Discover comprehensive answers from knowledgeable members of our community, covering a wide range of topics to meet all your informational needs.

A sample of argon gas is cooled and its volume went from 380 mL to 250 20 points
ml. If its final temperature was -55°C, what was its original temperature?

A Sample Of Argon Gas Is Cooled And Its Volume Went From 380 ML To 250 20 Points Ml If Its Final Temperature Was 55C What Was Its Original Temperature class=

Sagot :

DynamoPrince2612idn

Answer:

Applying the Laws of Thermodynamics we get as,

Explanation:

V1/T1 = V2/T2

According to the law of Gaseous states.

so we get as,

V1 = 380 ml, V2 = 250 ml, T2 = -55°C ==> 273-55 ==> 218 Kelvin.

so now substituting we get as,

380/ T1 =250/218

==> 380*(218) /250 = T1

==> T1 = 331.36 ===>T1 = 331 K approx

So the Original Temperature was 331 K,

Option 1.) is correct.

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.