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Sagot :
The proportion of oxygen to hydrogen by mass in the water is 8 : 1
Data obtained from the question
- Mass of CuO = 8.50 g
- Mass of Cu = 6.58 g
- Mass of water = 2.16g
- Proportion =?
How to determine the mass of O in water
- 1 mole of water (H₂O) = (2×1) + 16 = 18 g
- Mass of O in water = 16 g
18 g of water contains 16 g of O.
Therefore,
2.16 g of water will contain = (2.16 × 16) / 18 = 1.92 g of O
How to determine the mass of H in water
- Mass of water = 2.16 g
- Mass of O in water = 1.92 g
- Mass of H =?
Mass of H = mass of water – mass of O
Mass of H = 2.16 – 1.92
Mass of H = 0.24 g
How to determine the proportion of oxygen to hydrogen
- Mass of O = 1.92 g
- Mass of H = 0.24 g
- Proportion =?
Proportion = oxygen / hydrogen
Proportion = 1.92 / 0.24
Proportion = 8 : 1
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