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Sagot :
Hi there!
We can use the following kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
The initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad[/tex]
vf = final velocity (? m/s)
a = acceleration due to gravity (g)
d = vertical height (m)
Plug in the givens and solve:
[tex]v_f = \sqrt{2gd} = \sqrt{2(9.8)(173)} = \boxed{58.23 \frac{m}{s}}[/tex]
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