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Sagot :

Step-by-step explanation:

we can find value of x and y through Pythagoras theorem

according to it

h² = a² + b²

h = hypotenuse (i.e longest side of a right angled triangle)

a = side

b = base

in ∆ABC

AB² = AC² + BC²

(10)² = (8)² + x²

100 = 64 + x

x = 100 - 64 = 36

x² = √36 = 6

x = 6

in ∆PQR

PQ² = PR² + RQ²

y² = (4)² + (3)²

y = 16 + 9

y = 25

y² = √25 = 5

y = 5

a) angle BAC = angle QPR

b) value of x = 6 cm

c) value of y = 5 cm

hope this helps you dear!

Answer:

Step-by-step explanation:

When the triangles are similar

[tex]\frac{AC}{PR}=\frac{AB}{PQ} =\frac{BC}{QR} \\\\[/tex]

Taking First and Third ratios

[tex]\frac{AC}{PR} =\frac{BC}{QR} \\\\\frac{8}{4} =\frac{x}{3} \\\\x=\frac{8*3}{4} \\\\x=6cm[/tex]

Taking First and Second ratios

[tex]\frac{AC}{PR} =\frac{AB}{PQ} \\\\\frac{8}{4} =\frac{10}{y} \\\\y=\frac{4*10}{8}\\\\ y=5cm[/tex]

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