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Sagot :
Step-by-step explanation:
we can find value of x and y through Pythagoras theorem
according to it
h² = a² + b²
h = hypotenuse (i.e longest side of a right angled triangle)
a = side
b = base
in ∆ABC
AB² = AC² + BC²
(10)² = (8)² + x²
100 = 64 + x
x = 100 - 64 = 36
x² = √36 = 6
x = 6
in ∆PQR
PQ² = PR² + RQ²
y² = (4)² + (3)²
y = 16 + 9
y = 25
y² = √25 = 5
y = 5
a) angle BAC = angle QPR
b) value of x = 6 cm
c) value of y = 5 cm
hope this helps you dear!
Answer:
Step-by-step explanation:
When the triangles are similar
[tex]\frac{AC}{PR}=\frac{AB}{PQ} =\frac{BC}{QR} \\\\[/tex]
Taking First and Third ratios
[tex]\frac{AC}{PR} =\frac{BC}{QR} \\\\\frac{8}{4} =\frac{x}{3} \\\\x=\frac{8*3}{4} \\\\x=6cm[/tex]
Taking First and Second ratios
[tex]\frac{AC}{PR} =\frac{AB}{PQ} \\\\\frac{8}{4} =\frac{10}{y} \\\\y=\frac{4*10}{8}\\\\ y=5cm[/tex]
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