Get detailed and accurate responses to your questions on IDNLearn.com. Discover thorough and trustworthy answers from our community of knowledgeable professionals, tailored to meet your specific needs.

In triangle PQR, A and B are points on side QR such that they trisect QR. Prove that, ar( triangle PBR) = 0.5 ar( triangle PQB).

pls give the answer with steps...pls help me guys


Sagot :

Explanation:

We assume the problem statement is telling us that the order of points on segment QR is Q, A, B, R, and that QA = AB = BR. This means that

  QB = QA +AB = 2BR

  BR = 1/2(QB)

The area of the triangles will be ...

  A = 1/2bh

For triangle PQB, the area is ...

  ar(PQB) = 1/2(QB)h . . . . . h is the perpendicular distance from QR to P

For triangle PBR, the area is ...

  ar(PBR) = 1/2(BR)h = 1/2(1/2QB)h . . . . h is the same as above

  ar(PBR) = 1/2ar(PQB)

__

Essentially, you're showing the base of the smaller triangle is 1/2 the base of the larger one and using that to show the area of the smaller triangle is 1/2 the area of the larger one. (Both have the same height.)

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.